Matematika Sekolah Menengah Pertama 1.tentukan hasil perkalian dan bentuk aljabar berikut :
a.5(3×+7)
b. -8 (6a×-11)
c.(5×+6)(4×+5)
d. ((7×-2) (4×+5)
e. (9×-5)(2×-11)

1.tentukan hasil perkalian dan bentuk aljabar berikut :
a.5(3×+7)
b. -8 (6a×-11)
c.(5×+6)(4×+5)
d. ((7×-2) (4×+5)
e. (9×-5)(2×-11)

[tex]{ \huge{ \textup{ \blue{jawaban}}}}[/tex]

[tex] \large a. \: 5(3x + 7)[/tex]

[tex]{ \large{ \blue{ \bold{ = 15x + 35}}}}[/tex]

-

[tex] \large b. \: - 8(6ax - 11)[/tex]

[tex]{ \large { \blue{ \bold{= - 48ax + 88}}}}[/tex]

-

[tex] \large c. \: (5x + 6)(4x + 5)[/tex]

[tex] \large = 5x(4x + 5) + 6(4x + 5)[/tex]

[tex] \large = 20 {x}^{2} + 25x + 24x + 30[/tex]

[tex]{ \large { \blue{ \bold{= 20 {x}^{2} + 49x + 30 }}}}[/tex]

-

[tex] \large d. \: (7x - 2)(4x + 5)[/tex]

[tex] \large = 7x(4x + 5) - 2(4x + 5)[/tex]

[tex] \large = 28 {x}^{2} + 35x - 8x - 10[/tex]

[tex]{ \large { \blue{ \bold{= 28 {x}^{2} + 27x - 10 }}}}[/tex]

-

[tex] \large e. \: (9x - 5)(2x - 11)[/tex]

[tex] \large = 9x(2x - 11) - 5(2x - 11)[/tex]

[tex] \large = 18 {x}^{2} - 99x - 10x + 55[/tex]

[tex]{ \large { \blue{ \bold{= 18 {x}^{2} - 109x + 55 }}}}[/tex]

Pelajari lebih lanjut

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Detail Jawaban

Mapel : Matematika

Kelas : 7

Bab : 2.1 - Operasi Bentuk Aljabar

Kata kunci : Perkalian Aljabar.

Kode : 7.2.2.1

Jawaban:

5(3x + 7)

= 5.3x + 5.7

= 15x + 35

-8(6ax - 11)

= -8.6ax - (-8.11)

= -48ax + 88

(5x + 6)(4x + 5)

kali pelangi

= 20x² + 25x + 24x + 30

= 20x² + 49x + 30

(7x - 2)(4x + 5)

= 28x² + 35x - 8x - 10

= 28x² + 27x - 10

(9x - 5)(2x - 11)

= 18x² - 99x - 10x + 55

= 18x² - 109x + 55

semoga membantu,

met belajar skuy :)

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